Answer:
Option C. 11.2 L
Step-by-step explanation:
From the question given above, the following data were obtained:
Initial temperature (T₁) = 25.0 °C
Initial volume (V₁) = 8.66 L
Final temperature (T₂) = 112 °C
Pressure = constant
Final volume (V₂) =?
Next, we shall convert celsius temperature to Kelvin temperature. This can be obtained as follow:
T(K) = T(°C) + 273
Initial temperature (T₁) = 25 °C
Initial temperature (T₁) = 25 °C +273
Initial temperature (T₁) = 298 K
Final temperature (T₂) = 112 °C
Final temperature (T₂) = 112 °C + 273
Final temperature (T₂) = 385 K
Finally, we shall determine final volume of the gas. This can be obtained as follow:
Initial temperature (T₁) = 298 K
Initial volume (V₁) = 8.66 L
Final temperature (T₂) = 385 K
Pressure = constant
Final volume (V₂) =?
V₁/T₁ = V₂/T₂
8.66/298 = V₂/385
Cross multiply
298 × V₂ = 8.66 × 385
298 × V₂ = 3334.1
Divide both side by 298
V₂ = 3334.1 / 298
V₂ = 11.2 L
Thus, the final (i.e new) volume of the gas is 11.2 L