We will have the following:
First, we transform the revolutions per second to radians, that is:
![\begin{cases}-420rev/\min =-840\pi/\min =-14\pi/s \\ \\ 610\text{rev}/\min =1220\pi/\min =(61\pi)/(3)/s\end{cases}](https://img.qammunity.org/2023/formulas/physics/high-school/n5aa5r4xmi9w2om7hrn9qlly3atyqbnza5.png)
Now, we will have that the final angular velocit will be given by:
![-14\pi/s+(6\pi)/(3)/s=-12\pi/s](https://img.qammunity.org/2023/formulas/physics/high-school/lyjyqnj0jm526nouy5jx8ivkvtyyodawps.png)
So, the angular speed after coupling is -12pi/s. [That is the total angular speed will be counterclock wise]