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5 votes
5 votes
In a dihybrid cross, if the genotypes of one the parents is BbTT, what genes would you put on the outside of the Punnett square?

Answers:

BT, Bt, BT, Bt

BT, BT, BT, BT

BB, bb, TT, tt

BT, BT, bT, bT

User Non
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2 Answers

15 votes
15 votes

Answer:

BT,BT,bT,bT

Step-by-step explanation:

It's 50/50.

User Yogurt The Wise
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2.3k points
9 votes
9 votes

Answer:

BT, BT, bT, bT

Step-by-step explanation:

According to Mendel's law of independent assortment, the alleles of a gene will separate into gametes independently of one another i.e. one allele of a gene does not hinder the separation of another. The separation occurs via meiosis in such a way that only one allele of a gene is present in each GAMETE.

These gametes are what forms the crossing basis in a punnet square. According to this question involving a dihybrid cross, the genotype of one of the parents is BbTT. The allelic combination of the gametes will be: BT, BT, bT, bT. These gametes will be put on the outside of the Punnett square.

User Eric Nordvik
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3.0k points