Question

Solve the system of linear equations by substitution 1/2x+2y=3 and 6y+1=x

Answer 1

Given:

`\begin{gathered} (1)/(2)x+2y=3 \\ -1x+6y=-1 \end{gathered}`

Requirement:

Solution of the equations

Step-by-step explanation:

`\begin{gathered} (1)/(2)x+2y=3 \\ -(1)/(2)x+(6)/(3)y=-(1)/(2) \end{gathered}`

by adding

`\begin{gathered} 4y=(5)/(2) \\ y=(5)/(8) \end{gathered}`

putting the value of y in first equation

`\begin{gathered} (1)/(2)x+2*(5)/(8)=3 \\ x=3.5 \end{gathered}`

Final Answer:

x = 0.625

y = 3.5