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3 votes
3 votes
which of the following trigonometric expressions are equal? a. sin(theta) b. cos(theta)tan(theta) c. 1/sec(theta) d. csc(theta) (1-cos^2(theta))​

User Alex Emilov
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1 Answer

21 votes
21 votes

Answer:

A & B

Explanation:

cos(theta)tan(theta) can be expressed as;

cos(theta)tan(theta) = cos(theta) × (sin(theta))/cos(theta).

cos(theta) cancels out to give; sin(theta)

Thus is equivalent to option A

User Mousius
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