Given: Two points: (6,3) and (-4,3)
Required: Equation of line passing through the two points.
Step-by-step explanation:
The slope of line passing through the points (6,3) and (-4,3) is
![\begin{gathered} m=(3-3)/(6-(-4)) \\ m=(0)/(10)=0 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/3h1qf4picpzc8u2lu5xchga1ndufqpd119.png)
So the slope is 0.
Equation of line passing through (6,3) with slope 0 is
![\begin{gathered} y-3=0(x-6) \\ y-3=0 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/ofg2y42l470za29nrbkqhyckbzt8nx20w3.png)
Thus the equation is
![y=3](https://img.qammunity.org/2023/formulas/mathematics/high-school/k5jcc8khpzeekpgozsmz1r9py0vnhffn6u.png)
Final Answer: The equation is y = 3.