1 Answer

IshaS · Answer 1 · 2023-09-27T15:14:14+0000

In the given figure:

$\begin{gathered} AE=BE \\ \angle1\cong\angle2 \end{gathered}$

Angles 3 and 4 are vertical angles, therefore, they are congruent.

Thus, triangles ACE and BDE are congruent by AA Congruence Theorem.

Since one pair of sides (AE and BE) is equal, it means all the other corresponding sides are also equal

Therefore:

$CE\cong DE$

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