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20 votes
20 votes
Solve the following equation algebraically:

-16 = 16x?
How many solutions does this equation have? Explain.
a. -1 = x3; One solution because only -1 will satisfy the equation.
b. -1 = x2; No real solution because there is no real number that, when squared, produces -1.
c. 1= x?: Two solutions because the square root of 1 is positive 1 and negative 1.
d. 1=-x?: One solution because only -1 will satisfy the equation.

User Shoham
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2.8k points

1 Answer

12 votes
12 votes
Divide both side by 16 and you get x=-1
User Aleks Korovin
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2.7k points
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