Question

I would like to know how to work out this problem.

Answer 1

Given:

`y=2\sin(3x-(\mu)/(7))+5`

Required:

To find the amplitude and period of the given sine function.

Step-by-step explanation:

Consider

`y=2\sin(3x-(\mu)/(7))+5`

Here the amplitude is 2.

And the period is

`=(2\pi)/(3)`

Final Answer:

Amlitude = 2 and period is

`(2\pi)/(3)`