Question

I need help on this question

Answer 1

Let's begin by identifying key information given to us:

The altitude BT bisects Line AC to form a right-angle (90 degrees)

`\angle BTA=((1)/(3)x-7)`

Since we know that angle BTA is 90 degrees, we proceed to solve as shown below:

`\begin{gathered} \angle BTA=90^(\circ) \\ ((1)/(3)x-7)=90 \\ \text{Add ''7'' to both sides, we have:} \\ (1)/(3)x=90+7 \\ (1)/(3)x=97 \\ x=97*3=291 \\ x=291 \end{gathered}`