Question

The square plates of a 3000-pF parallel-plate capacitor measure 40 mm by 40 mm and are separated by a dielectric that is 0.29 mm thick and completely fills the region between the plates. What is the dielectric constant of the dielectric?

Answer 1

The dielectric constant of the dielectric is determined as 61.44.

How to calculate the dielectric constant?

The dielectric constant of the dielectric is calculated as follows.

First we need to calculate the permittivity of the dielectric material.

ε = (Cd)/A

where;

• A is the area of the plate
• d is the diameter

• C is the capacitance

ε = (3000 x 10⁻¹² x 0.00029 m ) / (0.04 m x 0.04 m)

ε = 5.44 x 10⁻¹⁰ F/m

The dielectric constant is calculated as follows;

k = ε / ε₀

k = ( 5.44 x 10⁻¹⁰ F/m ) / (8.85 x 10⁻¹² F/m)

k = 61.44

Answer 2

The square plates of a 3000-pF parallel-plate capacitor measure 40 mm by 40 mm and are separated by a dielectric that is 0.29 mm thick and completely fills teh region between the plates.

Step-by-step explanation: