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User Highjump
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To graph a linear equation, we have to find its intercepts first.

First equation


y=-x-5

The y-intercept is found when x = 0


y=-0-5=-5

The x-intercept is found when y = 0.


\begin{gathered} 0=-x-5 \\ 5=-x \\ x=-5 \end{gathered}

The intercepts of the first equation are (0,-5) and (-5,0).

Second equation.


y=(1)/(2)x+7

When x = 0


\begin{gathered} y=(1)/(2)\cdot0+7 \\ y=7 \end{gathered}

When y = 9.


\begin{gathered} 9=(1)/(2)x+7 \\ 9-7=(1)/(2)x \\ (1)/(2)x=2 \\ x=4 \end{gathered}

The intercepts of the second equation are (0,7) and (4,9).

At last, we plot the points and draw the lines.

This is the question-example-1
User Moogal
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