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How many molecules are in 2.65 mol of dinitrogen oxide, N2O which is an anesthetic called "laughing gas"?

User Scadge
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The question requires us to calculate the number of molecules in 2.65 moles of dinitrogen oxide (N2O).

The Avogadro's number defines the number of units in 1 mol of any substance as 6.022 x 10^23 (units/mol). These units might be atoms, ions, molecules etc. depending on the nature of the substance.

Using the Avogadro's number, we can write:

1 mol N2O -------------------- 6.022 x 10^23 molecules

2.65 mol N2O -------------- x

Solving for x, we'll have:


x=\frac{(2.65\text{ mol N}_2O)*(6.022*10^(23)molecules)}{(1\text{ mol N}_2O)}=1.60*10^(24)molecules

Therefore, there are 1.60 x 10^24 molecules of N2O in 2.65 moles of this substance.

User SebaGra
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