Question

A proof involving triangle ABC is shown below what title best describes the proof

Answer 1

Given data:

The given figure of the triangle.

In the triangle ACD and triangle BCD.

`\begin{gathered} AC\cong BC(\text{given)} \\ \angle1\cong\angle2 \\ CD\cong CD(Common) \\ \Delta ACD\cong\Delta\text{BCD(side angle side SAS)} \\ \angle A\cong\angle B(CPCT) \end{gathered}`

Thus, option (B) is correct.