Answer:
89.8 feet
Explanation:
In ΔBCD, the measure of ∠D=90°, the measure of ∠B=75°, and DB = 93 feet. Find the length of BC to the nearest tenth of a foot.
We would solve the above question using Sine rule
The formula is given as:
DB/sin D = BC/sin B
93/sin 90 = BC/sin 75
We cross multiply
sin 90 × BC = 93 × sin 75
BC = 93 × sin 75/sin 90
BC = 89.83 feet
Approximately BC = 89.8 feet