Question

Some one explain it with steps plz​

Answer 1

Answer 2

The given molecule C_12 H_22 O_11 is sucrose.

Sucrose of not dissociable in water hence Vant Hoff factor is 1

i.e

i=1

molality=m=0.3

k=freezing point constant (As we don't need to find the perfect freezing point let's keep it constant)

`\boxed{\sf T_f=kmi}`

T_f is freezing point

For Sucrose

`\\ \sf\longmapsto T_f=1(0.3)k=0.3k`

Now.

Let's check Vant Hoff factor of each compound.

AlCl_3=4

CuCl_2=3

NaCl=2

C_6H_12O=1

Let's count Freezing point of each compound.

AlCl_3

m=0.075

`\\ \sf\longmapsto T_f=0.075(4)k=0.3k`

Option A is correct

CuCl_2

m=0.15

`\\ \sf\longmapsto T_f=0.15(3)k=0.75k`

NaCl:-

m=0.3

`\\ \sf\longmapsto T_f=0.3(2)k=0.6k`

Glucose:-

m=0.6

`\\ \sf\longmapsto T_f=0.6k`

Hence option A is correct

Done