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Use point-slope form to write the equation of a line that passes through the point(-1, 4) with slope 5/6

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In the question, we are asked to write the equation of a line that passes through the point (-1, 4) with slope 5/6. This can be seen below.

Step-by-step explanation

The formula is given as


y-y_1=m(x-x_1)

y=y coordinate of second point

y_{1}=y coordinate of point one

m=slope

x=x coordinate of second point

x_{1}=x coordinate of point one

Therefore


\begin{gathered} y-4=(5)/(6)(x-(-1)) \\ y-4=(5)/(6)(x+1) \end{gathered}

Answer:


y-4=(5)/(6)(x+1)

User Prakash Raman
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