Given the equation of the line:
![-6x+5y=30](https://img.qammunity.org/2023/formulas/mathematics/college/uebt7p1933y9z1dwrm4813box24xu3n66e.png)
The x-intercept is the point where the line crosses the x-axis, at this point the value of y is zero. To determine the x-intercept, replace the equation of the kine with y=0 and solve for x:
![\begin{gathered} -6x+5y=30 \\ -6x+5\cdot0=30 \\ -6x=30 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/rkf8gcyd2uqpgk6kwpddd5ei4og8dvqmgv.png)
Divide both sides by -6
![\begin{gathered} (-6x)/(-6)=(30)/(-6) \\ x=-5 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/akmf2ym5cfvdsidp47z0uwnx6it727xk6q.png)
The x-intercept of the line is (-5,0)