Question

Solve itttttttttttttt..​

Answer 1

a) cot∠B = ⇔ cot 60° ⇒ x = cot 60° × 6 = 2√3

b) sin∠C = ⇔ sin∠C = ⇒ ∠C = 30°

c) ΔABC is a isosceles right triangle ⇒ AB = BC

`AB^(2)+ BC^(2) =AC^(2) => 2AB^2=AC^2 \\=>AB^2=(AC^2)/(2) = ((5√(2) )^2)/(2) =25\\=>AB=x=√(25)=5 cm`

Ok done. Thank to me :>

Answer 2

Explanation: