Question

2Find the equation of the line thatis perpendicular to y = –x and3contains the point (4,-8).y =x + [

Answer 1

A line perpendicular to the given line should have a slope which is a negative reciprocal of the given slope.

In the given, the slope is -2/3. Thus, the new slope should be m=3/2.

To obtain the line with the slope 3/2 and passes through (4,-8), substitute the value of the slope and the coordinates into the point-slope formula and then simplify the right side of the equation.

`\begin{gathered} y=m(x-x_1)+y_1 \\ y=(3)/(2)(x-4)+(-8) \\ y=(3)/(2)(x-4)-8 \\ y=(3)/(2)x-6-8 \\ y=(3)/(2)x-14 \end{gathered}`

Thus, the values for the blanks should be 3, 2, and -14, respectively.