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Divide:2x^3+9x^2+10x+3 by 2x+1

User Nirkov
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1 Answer

6 votes

(2x^3+9x^2+10x+3)/(2x+1)

start rewriting the square term and the linear term


(2x^3+2x^2+7x^2+7x+3x+3)/(2x+1)

take the common factor


(2x^2(x+1)+7x\cdot(x+1)+3\cdot(x+1))/(2x+1)

factor the expression


((x+1)\cdot(2x^2+7x+3))/(2x+1)

rewrite the expression


((x+1)\cdot(2x^2+6x+x+3))/(2x+1)

take common factor


((x+1)\cdot(2x(x+3)+x+3))/(2x+1)

factor the expression


((x+1)\cdot(x+3)(2x+1))/(2x+1)

simplify


\begin{gathered} (x+1)(x+3) \\ x^2+x+3x+3 \\ x^2+4x+3 \end{gathered}

User Scott
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