Question

The first and thirteenth terms of an arithmetic sequence are $\frac79$ and $\frac45$, respectively. What is the seventh term

Answer 1

`\text{Given:} \\a_1=\frac79 \\ a_(13)=a_1+12d=\frac79+12d=\frac45 \\ \\\text{Find:} \\ a_7=a_1+6d`

Upon solving for d and substituting it into
`a_7`

`d=(1)/(45 * 12)\\\\a_7=\frac79+(6)/(45 * 12)=\frac79+(1)/(90)=(71)/(90)`