Question

A 11.54 kg cantaloupe takes 0.651s to launch, is launched off a 22.87 m-cliff with a resultant Force of 236.55 N. at an angle of at an angle 57.66° above the horizontal. Given gravity and Air resistance are accounted for at launch. What is the launch velocity of the Y axis?

Answer 1

We know that

• The mass is 11.54 kg.

,

• The time taken is 0.651 seconds.

,

• The distance covered is 22.87 meters.

,

• The resutant force is 236.55 N.

,

• The angle of launch is 57.66.

Let's use Newton's Second Law.

`\Sigma F_y=ma\to F-W=ma`

Where F = 236.55N, W = mg, m = 11.54kg, and g = 9.81 m/s^2.

The acceleration of the object is 10.7 m/s^2.

Now, let's find the initial vertical velocity.

`\begin{gathered} v_y=v_(oy)+gt \\ 0=v_(oy)-9.8\cdot0.651\sec \\ v_(0y)=6.4\cdot(m)/(s) \end{gathered}`

The initial vertical velocity is 6.4 m/s.