Question

Concentrated HCl is 12M. What volume is needed to make a 2L of 1M solution?Can you please help to solve and explain?

Answer 1

0.1667 L

Step-by-step explanation

Given:

Let the volume of the concentrated HCl be V₁

The concentration of the concentrated HCl, C₁ = 12 M

The volume of the diluted HCl, V₂ = 2 L

The concentration of the diluted HCl, C₂ = 1 M

What to find:

The volume of the concentrated HCl, V₁ needed to make a 2L of 1M solution.

Solution:

The volume of the concentrated HCl, V₁ needed to make a 2L of 1M solution can be calculated using the dilution formula.

`\begin{gathered} C_1V_1=C_2V_2 \\ \\ \Rightarrow V_1=(C_2V_2)/(C_1) \end{gathered}`

Put C₁ = 12 M, V₂ = 2 L, and C₂ = 1 M into the formula to get V₁

`V_1=(1M*2L)/(12M)=(2L)/(12)=0.1667\text{ }L`

Therefore, the volume of the concentrated HCl, V₁ needed to make a 2L of 1M solution is 0.1667 L