Question

Pls answer to this,

`(1 - 0.7) ^(2)`



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Answer 1

`(1-0.7)^(2) =1^2-2.1.(0.7)+(0.7)^2=1-1.4+0.49=0.09`

`(1-0.7)^(2) =(0.3)^2=0.09`

P/s:
`(A-B)^2=A^2-2AB+B^2`

Ok done. Thank to me :>

Answer 2

0.09

Explanation:

We can re-write 1-0.7 as 0.3

Now we have:

(0.3)² = 0.09