Question

What quadratic equation has solutions 2 and -1/3 use the variable X to write your equation

Answer 1

Given the roots,

2 and -1/3

Therefore we can write,

`(x-2)(x+(1)/(3))=0`

On solving,

`\begin{gathered} (x-2)(x+(1)/(3))=0 \\ x^2+(1)/(3)x-2x-(2)/(3)=0 \\ x^2+(x-6x)/(3)-(2)/(3)=0 \\ 3x^2-5x-2=0 \end{gathered}`