Answer:
a. y = 2x - 4
b. y = -3x + 7
c. y = 5x - 3
Step-by-step explanation:
The equation of a line with slope m that passes through the point (x1, y1) is
![y-y_1=m(x-x_1)](https://img.qammunity.org/2023/formulas/mathematics/high-school/csobd57zth7rh9k4hz9amldzpq2owf0z4j.png)
So, for each part, we get:
Part a.
The slope m = 2 and it passes through the point (x1, y1) = (3, 2)
![y-2=2(x-3)](https://img.qammunity.org/2023/formulas/mathematics/college/ju1rs1x5ud6vp5ivyf6zeqe2n13hk5d5lf.png)
Then, we can solve the equation for y, so
![\begin{gathered} y-2=2(x)-2(3) \\ y-2=2x-6 \\ y-2+2=2x-6+2 \\ y=2x-4 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/bu9i6s51fks01wxnd9a6k8ewsq1ny86j2c.png)
Part b.
In the same way, replacing m = -3 and (x1, y1) = (1, 4), we get
![\begin{gathered} y-4=-3(x-1) \\ y-4=-3x-3(-1) \\ y-4=-3x+3 \\ y-4+4=-3x+3+4 \\ y=-3x+7 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/fg5bqs42gounxw5qzphc5n2ppdoi44o4e2.png)
Part c.
Replacing m = 5 and (x1, y1) = (1, 2), we get:
![\begin{gathered} y-2=5(x-1) \\ y-2=5(x)+5(-1) \\ y-2=5x-5 \\ y-2+2=5x-5+2 \\ y=5x-3 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/rl4x29bu1k9l6d3xod0qo9msz8gdnnwlp2.png)
So, the answers are:
a. y = 2x - 4
b. y = -3x + 7
c. y = 5x - 3