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mixture of gas contains 10.0 mol of chlorine, cl2, and xenon, xe, gas. what is the mole fraction of chlorine gas if there are 5.0 mol cl2 in the mixture?

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Final answer:

The mole fraction of chlorine gas in the mixture is 0.3333.

Step-by-step explanation:

The mole fraction of a component in a gas mixture is the ratio of the number of moles of that component to the total number of moles in the mixture. In this case, the mixture contains 10.0 mol of chlorine gas (Cl2) and xenon gas (Xe). If there are 5.0 mol of Cl2 in the mixture, the mole fraction of chlorine gas can be calculated as:



Mole fraction of Cl2 = (moles of Cl2) / (moles of Cl2 + moles of Xe)



Mole fraction of Cl2 = 5.0 mol / (5.0 mol + 10.0 mol) = 5.0 mol / 15.0 mol = 0.3333



Therefore, the mole fraction of chlorine gas in the mixture is 0.3333.

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