Question

2

Type the correct answer in each box. Use numerals instead of words.
Multiply the expressions.
3.12 + 21 - 21
-212 - 21 + 12
212 + 251 + 63
612 + 71 - 49
If a = 1, find the values of b, c, and d that make the given expression equivalent to the expression below.
ar +
CI + d
b=
,and du
,C=
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Answer 1

`\begin{gathered} \frac{3x^2+2x-21}{-2x^2-2x\text{ +12}}*(2x^2+25x+63)/(6x^2+7x-49) \\ \\ (3x^2+9x-7x-21)/(-2x^2-6x+4x+12)*(2x^2+18x+7x+63)/(6x^2+21x-14x-49) \\ \\ (3x\mleft(x+3\mright)-7\mleft(x+3\mright))/(-2x(x+3)+4(x+3))*(2x(x+9)+7(x+9))/(3x(2x+7)-7(2x+7)) \\ \\ ((3x-7)(x+3))/((-2x+4)(x+3))*((2x+7)(x+9))/((3x-7)(2x+7)) \end{gathered}`

Cancelling out the common terms we have

`\begin{gathered} \frac{(3x-7)}{(-2x+4)_{}}*((x+9))/(3x-7)) \\ \text{cancelling out (3x-7) we have } \\ ((x+9))/((-2x+4)) \end{gathered}`

Therefore, from

`\begin{gathered} ((x+9))/((-2x+4)) \\ \text{if a =1, then b = 9, c = -2 and d = 4} \end{gathered}`

So, b = 9,

c = -2

d = 4