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43 votes
The heights of two cylinders are in the ratio of 5:3 and their volume are in the ratio 20:27. then the ratio of their radius is...... ?

plz its urgent

User Stadub Dima
by
2.3k points

2 Answers

12 votes
12 votes

Answer:

The ratio of their radius is
2:3

Explanation:

Volume of cylinder is
\pi r^2h, where r is radius and h is height

We have

The heights of two cylinders are in the ratio of
5:3


(h_1)/(h_2) =(5)/(3)

The volume are in the ratio
20:27


(V_1)/(V_2) =(20)/(27)\\\\(\pi r_1^2h_1)/(\pi r_2^2h_2) =(20)/(27)\\\\( r_1^2)/( r_2^2)* (3)/(5) =(20)/(27)\\\\( r_1^2)/( r_2^2) =(4)/(9)\\\\( r_1)/( r_2) =(2)/(3)

The ratio of their radius is
2:3

User Michael Daum
by
2.4k points
17 votes
17 votes

Answer:

2 : 3

Explanation:

Let,

Radius of cylinder 1 = R

Radius of cylinder 2 = r

Now,

We know that

Volume of cylinder = πr²h

=> πR²h/πr²h' = 20/27

=> R² × 5/r² × 3 = 20/27

=> R²/r² = 20/27 × 3/5

=> R²/r² = 4/9

=> R/r = √(4/9)

=> R/r = 2/3

=> R : r = 2 : 3

User Sushrut
by
2.8k points
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