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If f is a one-to-one function and f(2)=5, then f^-1(5)= __A 1/5B 2C 5

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The one to one function define as a output is fix for one input

so for x give value a then invers of a is x that mean:


\begin{gathered} f(2)=5 \\ f^(-1)(5)=2 \end{gathered}

If f is a one-to-one function and f(2)=5, then f^-1(5)= __A 1/5B 2C 5-example-1
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