Question

Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and one same-day ticket is $55 . For one performance, 35 advance tickets and 40 same-day tickets were sold. The total amount paid for the tickets was $2050. What was the price of each kind of ticket?

Answer 1

This is a simple question to solve.

Let's consider advanced tickets are represented by the variable "x" and same-day tickets are represented by the variable "y". So, once 1 advanced tickets + 1 same-day ticket is equal to $ 55 it means x + y = 55. Now we also have a different situation, 35 advance tickets and 40 same-day tickets were sold with a total of $2050, so 35x + 40y = 2050. We can see we have 2 equations so we have a system and we can solve is as follows:

Once we found y, we can substitute as follows:

So finally our final answer is:

advanced ticket costs $30

same-day ticket costs $25