428,662 views
22 votes
22 votes
A train is moving at 65.0 m/s. After 16.0 seconds, it is moving at 85.0 m/s. What is the acceleration?

A train is moving at 65.0 m/s. After 16.0 seconds, it is moving at 85.0 m/s. What-example-1
User Ran Yefet
by
3.2k points

2 Answers

9 votes
9 votes

Answer:

Hope it will help you...

A train is moving at 65.0 m/s. After 16.0 seconds, it is moving at 85.0 m/s. What-example-1
User Axilmar
by
2.8k points
5 votes
5 votes

Happy Holidays!

We can use the following equation to calculate uniform acceleration:


\large\boxed{a = (\Delta v)/(\Delta t) = (v_f - v_i)/(\Delta t)}}

Plug in the given values to solve:


(85 - 65)/(16)}} = (20)/(16) = \boxed{1.25 m/s^2}}

User Aneesah
by
2.7k points