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Can you help me with this question?points (3,1) and (5,-1)

Can you help me with this question?points (3,1) and (5,-1)-example-1

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Given the points (3,1) and (5,-1), we can find the slope with the following formula:


m=(y_2-y_1)/(x_2-x_1)

In this case we have the following:


\begin{gathered} m=(-1-1)/(5-3)=(-2)/(2)=-1 \\ m=-1 \end{gathered}

now that we have that the slope is m = -1, we can find the equation using the first point and the point-slope formula:


\begin{gathered} y-y_1=m(x-x_1) \\ \Rightarrow y-1=-1(x-3)=-x+3 \\ \Rightarrow y=-x+3+1=-x+4 \\ y=-x+4 \end{gathered}

therefore, the equation of the line is y = -x+4

User Francois Verbeeck
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