Question

In the Kite ABCD, AB = 52‾√52 mm AP= 5 mm, PD = 7 mm, find the area to the nearest mm2.

Answer 1

`\begin{equation*} 140\text{ mm}^2 \end{equation*}`

Step-by-step explanation

Step 1

the area of a kite is given by:

The area of a kite is half the product of the lengths of its diagonals

`Area=x*y`

Step 1

given the rigth triangle

so, we can find the x and y values

hence

a)x

`\begin{gathered} (x)/(2)=\text{ 5} \\ to\text{ solve for x, multiply both sides by 2} \\ (x)/(2)*2=5*2 \\ x=10 \end{gathered}`

b) y

`\begin{gathered} (y)/(2)=7 \\ to\text{ solve for y, multiply both sides by 2} \\ (y)/(2)*2=7*2 \\ y=14 \end{gathered}`

so

x=10

y=14

Step 2

finally, replace in the formula to find the area

`\begin{gathered} Area=xy \\ area=10\text{ mm *14 mm} \\ area=140\text{ mm}^2 \end{gathered}`

therefore, the answer is

`\begin{equation*} 140\text{ mm}^2 \end{equation*}`

I hope this helps you