Question

Find the coordinates of the point 3/10 of the way from A to B.A= (-4,-8)B=(10,6)

Answer 1

Starting point:

A=(-4 , -8)

Final point:

B= (10 , 6)

First we have to substract the first x-value from the second, we will get:

10- (-4)=14

Now, substracting the first y-value form the second:

6 - (-8)= 6+8= 14

Since both legs are the same, this makes a triangle isoceles, this is because the slope of our line is 1

`m=(y_2-y_1)/(x_2-x_1)=(14)/(14)=1`

Now, we have to multiply the lenght of each leg by 3/10:

`14*(3)/(10)=(21)/(5)=4.2`

Remember that both length are the same. Therefore, we have to add 4.2 to -4 and -8 to find the coordinates of the point 3/10 of the way from A to B:

`\begin{gathered} A=(-4.-8) \\ Ca=(-4+4.2,-8+4.2)=(0.2,-3.8) \end{gathered}`

Answer: The coordinates are (0.2 , -3.8).