Given:
The function is:
![b(x)=\begin{cases}0.15x,.........................\text{ }x\leq360 \\ 0.10(x-360)+54,\text{ ......}x>360\end{cases}](https://img.qammunity.org/2023/formulas/mathematics/college/tpqk1tiau4bnpnjuhsrxdo3y9jnq2ypsah.png)
Find-:
How much is the bill for a person who uses 560 KWh in a month
Explanation-:
Uses of 560 KWh in a month
![x=560](https://img.qammunity.org/2023/formulas/mathematics/college/68gs13rcrmkfutn1n32bj0ry7xawvp4xxk.png)
For x = 560 function apply is:
![b(x)=0.10(x-360)+54.................x>360](https://img.qammunity.org/2023/formulas/mathematics/college/qxwbign3eeebto21r3iuxy0a2gqbkyf1lh.png)
When x is greater than 360 so function b(x) second use.
![b(x)=0.10(x-360)+54](https://img.qammunity.org/2023/formulas/mathematics/college/6c86niwm79897cml84im6e2t7cd40yv2q5.png)
Function value at x = 560 is:
![\begin{gathered} b(x)=0.10(x-360)+54 \\ \\ b(560)=0.10(560-360)+54 \\ \\ b(560)=0.10(200)+54 \\ \\ b(560)=20+54 \\ \\ b(560)=74 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/od44exiobrjsqzs516tcn3hugi9sjmieq4.png)
The value at 560 KWh value is $74.