Question

Find the number of outcomes when n = 6 and r = 3. n!
(n−r)!r!

Answer 1

20

Explanation:

This is the formula for a combination. Substitute the values and evaluate the expression.

`(n!)/(r!(n-r)!)\\\\((6)!)/((3)!(6-3)!)\\\\((6)!)/((3!)(3!))\\\\((6\cdot5\cdot4\cdot3\cdot2\cdot1))/((3\cdot2\cdot1)(3\cdot2\cdot1))\\\\(720)/((6)(6))\\\\(720)/(36)\\\\ 20`