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Howard Hoffman · Answer 1 · 2023-03-22T08:54:33+0000

Given the function;

First, we find the inverse of the function as;

$\begin{gathered} \operatorname{Re}place\text{ x with y, we have;} \\ x=(1)/(y+3)+2 \\ \text{Then, solve for y, we have;} \\ y=(-3x+7)/(x-2) \end{gathered}$

Then, we get the domain of the inverse function, we have;

$x<2\text{ or x>2}$

Thus, the graph of the function is;

Hence, the range of the function is;

$\mleft\lbrace y\colon y\in\mathfrak{\Re },y\\e2\mright\rbrace$

CORRECT OPTION: B

What is the range for the following function? V x + 3 1 + 2 +3 A. {»:YER, 23) O B-example-1

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