Question

John recently joined a bowling team and each night plays three games. During his first two games he scored 112 and 134. What must John score on his last game to ensure his average for that night will be exactly 132?explain pls.

Answer 1

Let the score in his last game be

`=x`

The average of the three games is given as

`=132`

Step 1: The formula for average is

`\text{average}=\text{ }\frac{\text{sum of the thre}e\text{ scores}}{3}`

Step 2:Substituting the values of the three scores in the formula above, we will have

`\begin{gathered} \text{average}=\text{ }\frac{\text{sum of the thre}e\text{ scores}}{3} \\ \text{average}=(112+134+x)/(3)=132 \end{gathered}`

Step 3 : Cross multiply the equation below

`\begin{gathered} (112+134+x)/(3)=(132)/(1) \\ (246+x)/(3)=(132)/(1) \\ 246+x=3*132 \\ 246+x=396 \end{gathered}`

Step 4: Subtract 246 from both sides

`\begin{gathered} 246+x=396 \\ 246-246+x=396-246 \\ x=150 \end{gathered}`

Hence,

John must score a point of 150 to ensure that his average is 132

Therefore,

Final answer = 150