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(Classify the segment) Math Help Quick Please!

(Classify the segment) Math Help Quick Please!-example-1
User Helana
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2 Answers

19 votes
19 votes

#a

  • Perpendicular bisector of
    \overline {JL}
  • Angle bisector of K
  • Median of JKL
  • Altitude of JKL


\red{ \rule{35pt}{2pt}} \orange{ \rule{35pt}{2pt}} \color{yellow}{ \rule{35pt} {2pt}} \green{ \rule{35pt} {2pt}} \blue{ \rule{35pt} {2pt}} \purple{ \rule{35pt} {2pt}}

#b

  • None of the above


\red{ \rule{35pt}{2pt}} \orange{ \rule{35pt}{2pt}} \color{yellow}{ \rule{35pt} {2pt}} \green{ \rule{35pt} {2pt}} \blue{ \rule{35pt} {2pt}} \purple{ \rule{35pt} {2pt}}

#c

  • Perpendicular bisector of
    \overline {</em><em>QR</em><em>}
  • }[/tex]Angle bisector of ∠P
  • Median of △PQR
  • Altitude of △PQR
User Yohst
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2.9k points
16 votes
16 votes

Answer:

(a) Altitude

(b) perpendicular bisector

(c) median

Explanation:

  • The perpendicular bisector of a side of a triangle is a line perpendicular to the side and passing through its midpoint.
  • The angle bisector of an angle of a triangle is a straight line that divides the angle into two congruent angles.
  • A median of a triangle is a line segment drawn from a vertex to the midpoint of the opposite side of the vertex.
  • An altitude of a triangle is the perpendicular segment from a vertex of a triangle to the opposite side (or the line containing the opposite side).

(a) Altitude

m∠KML = 90° but JM ≠ ML (so not perpendicular bisector)

(b) perpendicular bisector

AD = DB and m∠BDE = 90°

(c) median

QS = QR ⇒ S is the midpoint QR, BUT it is not perpendicular to QR, so median

User Anton Tykhyy
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