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Solve the following quadratic equation by using the quadratic formula. If needed, submit your answer as a fraction reduced to lowest terms or round your answer to two decimal places

Solve the following quadratic equation by using the quadratic formula. If needed, submit-example-1
User Sophi
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1 Answer

7 votes

Solution

Solve the following quadratic equation by using the quadratic formula


3z^2-2z=0
z=(-b\pm√(b^2-4ac))/(2a)
\begin{gathered} 3z^2-2z+0=0 \\ a=3,b=-2,c=0 \end{gathered}
\begin{gathered} z=(-(-2)\pm√((-2)^2-4(3)(0)))/(2(3)) \\ z=(2\pm√(4))/(6) \\ z=(2\pm2)/(6) \\ z=(2+2)/(6),(2-2)/(6) \\ z=(4)/(6),(0)/(6) \\ x=(2)/(3),0 \end{gathered}

Therefore the correct answer is


z=(2)/(3),0

User Bill DeRose
by
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