Question

Solve for x3x^2 + 2x - 5 = 0

Answer 1

Step-by-step explanation

Given

`3x^2+2x-5=0`
`\begin{gathered} \mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:} \\ x_(1,\:2)=(-b\pm √(b^2-4ac))/(2a) \end{gathered}`

Therefore;

`\begin{gathered} \mathrm{For\:}\quad a=3,\:b=2,\:c=-5 \\ x_(1,\:2)=(-2\pm √(2^2-4\cdot \:3\left(-5\right)))/(2\cdot \:3) \\ x_(1,\:2)=(-2\pm \:8)/(2\cdot \:3) \\ separate\text{ solutions} \\ x_1=(-2+8)/(2\cdot \:3),\:x_2=(-2-8)/(2\cdot \:3) \\ x_1=(6)/(6)x_2=(-10)/(6) \\ x_1=1\text{ },x_2=(-5)/(3) \end{gathered}`

Answer:

`x_(1)=1\text{,}x_(2)=(-5)/(3)`