Question

Solve (x + 3)^2 – 5 = 0 using the quadratic formula.

Answer 1

Okay, here we have this:

Considering the provided equation, we are going to solve it using the quadratic formula, so we obtain the following:

`\begin{gathered} \mleft(x+3\mright)^2-5=0 \\ x^2+6x+9-5=0 \\ x^2+6x+4=0 \\ x_(1,\: 2)=(-6\pm√(6^2-4\cdot\:1\cdot\:4))/(2\cdot\:1) \\ x_(1,\: 2)=(-6\pm\:2√(5))/(2\cdot\:1) \\ x_1=(-6+2√(5))/(2\cdot\:1),\: x_2=(-6-2√(5))/(2\cdot\:1) \\ x=-3+√(5),\: x=-3-√(5) \end{gathered}`

Finally we obtain that the correct answer is the option A.