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Y=x^2-6x+2 write vertex form

User MSafdel
by
5.9k points

1 Answer

4 votes

Given:

The equation is y = x²-6x+2.

The objective is to write the equation in vertex form.

The equation can be converted into a perfect square equation by adding +9 on both sides of the equation.


\begin{gathered} y=x^2-6x+2 \\ y+9=x^2-6x+9+2 \\ y=x^2-6x+9+2-9 \\ y=\lbrack(x-3)(x-3)\rbrack-7 \\ y=(x-3)^2-7 \end{gathered}

User Dahn
by
7.0k points
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