We are given the expression;
![12+30y](https://img.qammunity.org/2023/formulas/mathematics/college/t0ruevfyohjvzwu7xnpfm6e4tthp0nq56b.png)
To factor a given expression, we take each part separately and look for any factors that can divide both without remainders.
Looking at the first one;
![12=2*2*3](https://img.qammunity.org/2023/formulas/mathematics/high-school/qh09vjobgio6pj30ubi91oghpq1y6t812a.png)
And then the other one;
![30y=2*3*5* y](https://img.qammunity.org/2023/formulas/mathematics/college/qq52hlm6v5q5zempz2wamrlnbh0lbuas6z.png)
Notice that 2 and 3 afre common factors (that is 2 times 3 = 6).
Hence, we can factor out 6 from both parts of this expression as follows;
![(12)/(6)+(30y)/(6)](https://img.qammunity.org/2023/formulas/mathematics/college/cyu3ufzghsl16qcrbpdi5x33urd04fhx6r.png)
Or if you want it to look more simplified (for the sake of understanding the steps better);
![\begin{gathered} ((2*2*3))/(2*3)+((2*3*5* y))/(2*3) \\ =2+(5* y) \\ =2+5y \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/4m7jkii7fttad283ma9s0stlmk6jh06j5a.png)
This means we can now re-write after factoring out 6;
![6(2+5y)](https://img.qammunity.org/2023/formulas/mathematics/college/bjkioiwpg0y7i407s0me4n8f8rmf538qs2.png)
That is;
![12+30y=6(2+5y)](https://img.qammunity.org/2023/formulas/mathematics/college/36h7fm9jsce7kujw7y0qbldo0q1v051zkb.png)
ANSWER:
![6(2+5y)](https://img.qammunity.org/2023/formulas/mathematics/college/bjkioiwpg0y7i407s0me4n8f8rmf538qs2.png)