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Moments after making the dreaded decision to jump out the door of the airplane, a skydiver's 89.5-kg body experiences 130 N of air resistance. The magnitude of the skydiver's downward acceleration at this instant in time is ______ m/s^2. Use the approximation g ≈ 10 m/s^2.

1 Answer

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Given:

The mass of the skydiver is,


m=89.5\text{ kg}

The air resistance is,


R=130\text{ N}

To find:

The downward acceleration of the skydiver

Step-by-step explanation:

The resultant downward force is,


\begin{gathered} F_(net)=mg-R \\ =89.5*10-130 \\ =765\text{ N} \end{gathered}

The downward acceleration is,


\begin{gathered} a=(F_(net))/(m) \\ =(765)/(89.5) \\ =8.55\text{ m/s}^2 \end{gathered}

Hence, the downward acceleration is,


8.55\text{ m/s}^2

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