Given an Inverse Variation in which "y" varies inversely as "x", you need to remember the form of an Inverse Variation Equation:
![y=(k)/(x)](https://img.qammunity.org/2023/formulas/mathematics/college/553kf23di4ua2hg2wlq29izw2itydfmguh.png)
Where "k" is the Constant of variation.
In this case, you know that when:
![x=4](https://img.qammunity.org/2023/formulas/mathematics/college/clnezaiwnjqx862gnqh94au9b279p8untt.png)
The value of "y" is:
![y=2](https://img.qammunity.org/2023/formulas/mathematics/college/qnigwn4qimkv1jqiimwsqzjpnbrgi3na3e.png)
Then, you can substitute values into the equation and solve for "k":
![\begin{gathered} 2=(k)/(4) \\ \\ 4\cdot2=k \\ k=8 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/2r4w0dnpiiebf69ac658pmycpmklb2l09t.png)
Therefore, the equation describing the relationship given in the exercise has this form:
![y=(8)/(x)](https://img.qammunity.org/2023/formulas/mathematics/college/qmm2c2l89fow86kcl8icodq3ouv5d1vho8.png)
Hence, the answer is:
- Equation:
![y=(8)/(x)](https://img.qammunity.org/2023/formulas/mathematics/college/qmm2c2l89fow86kcl8icodq3ouv5d1vho8.png)
- The numerator is:
![8](https://img.qammunity.org/2023/formulas/mathematics/high-school/yhwsr0hj9zc72y2rvqxvnjk2buonrgs3z6.png)
- The denominator is:
![x](https://img.qammunity.org/2023/formulas/mathematics/high-school/7i9rhkmy8weow049o4r221u9e7b2s5rdwo.png)