Question

A bowling ball rolls down a lane that is 45 meters long in 7.5 seconds. What was the magnitudeof the bowling ball's average velocity?1) v = 0.17 m/s2) v = 6 m/s3) v = 337.5 m/s4) v = 45 m/s

Answer 1

Given information:

Distance covered by the bowling ball;

`s=45\text{ m}`

Time taken;

`t=7.5\text{ s}`

The average velocity of the bowling ball is given as,

`v_(av)=(s)/(t)`

Substituting all known values,

`\begin{gathered} v_(av)=\frac{45\text{ m}}{7.5\text{ s}} \\ =6\text{ m/s} \end{gathered}`

Therefore, the magnitude of the bowling ball's average velocity is 6 m/s. Hence, option (2); v=6 m/s is the correct choice.