Question

A 667.984L sample of F2 experiences a change in pressure from 675.33 kPa to 981.94 kPa. What is the resulting volume in Liters?

Answer 1

We will assume that the gas behaves like an ideal gas, also that the temperature and moles of the gas are constant. Since there is only a change in volume and pressure, we can apply Boyle's law, which tells us:

`P_1V_1=P_2V_2`

Where,

P1 is the initial pressure of the gas, 675.33kPa

V1 is the initial volume of the gas, 667.984L

P2 is the final pressure of the gas, 981.94kPa

V2 is the final volume of the gas

We clear V2 and replace the known data:

`V_2=(P_1V_1)/(P_2)`
`V_2=(675.33kPa*667.984L)/(981.94kPa)=459.41L`

Answer: The volume resulting in liters is 459.41 L